-6*(7-12)+15*(1-20/4)-(-13)
6%.50
6%x50
21c / -3b
5 x al cuadrado por x al cuadrado
2.5 x mx
10x ^ { 3a } -15x ^ { 2a } +20x ^ { 2a-1 } \div 5x ^ { a }
how can we be absolutely certain that two triangles are congruent?
(6x5)−13≤−13(\frac{6x}{5}) - \frac{1}{3} \leq -\frac{1}{3}(56x)−31≤−31
