v^1.35 = 0.81826
-5(2t+9)=-65
{24-[35-(7+4-6)-(3+12)]}+57
(3a-2ba)^3
395000÷500
4000
-
3516
(A−B)∪(A−C)∪(B−C)
2/x + 2/3-x
4(f-8)=-36
a=1+√3i/2 ,b = 1-√3i/2 prove that a^3b^4+a^2b^3+ab^2+b=1