if 4 by 5 of a number exceeds AIDS to by 3 by 8 then the number is
6a + 10b = 1/8
4a + 6b = 1/10
$$\int_{\(0)}^{\(x)}(\(1/( $x^{1/3}$ ))) d\(x)$$
2(y-1)+3(2y+5)
factorize 5x squared + 3x -2
x^3 = 338
x=
factorize x(a+b)+3(a+b)
74.9963 rounded to two decimal places
factorize x squared + x - 6
$$\int_{\(0)}^{\(x)}((\1/x^3)) d\(x)$$