252^{5}25
6/2(2+1)
6 □□\frac{\Box}{\Box}□□ 2(2+1)
32/97,25
1\frac{3}{4}\div \frac{5}{3}
3\frac{3}{8}\div 3\frac{3}{8}
7\frac{1}{2}\div 12
17+5+3+16+10+17
.If x = 1+√2 , find the value of (𝑥 −
1
𝑥
)
3
.
23*x^3-23*x^2+6*x-1 = 0