6/2(1+2)
Find K if its vertex is in the abscissa axis
f(x) = -Kx^2 +6x + ¼
(x^2-4)/(2x-4)
[(x^2-4)/(2x-4)']
derivative of ,
1. y=e^x/2 y^(8)
2. y=x^8 y^(6)
\frac{2a^4\cdot 3a^6}{6a^5\cdot 5a}
7 × 1/3
(-31x^5u+24x^5u^5)/(-4x^4u^2)
2890= x+0.15x+x0.10+0.12(x+0.15x+x0.10)