(9/($x-2)^{2}$)+(6/(x-2))
factorize 15y-12
What is the upper quartile of the given ages - 20, 16, 23, 20, 19, 21, 19, 25, 19, 20, 20, 20, 17, 20, 19, 17, 19, 20
(9/($x^{2}$ -x))+(6/x-2)
x^2+y^2+4x+6y+16=0
factorize 3x+6
Simplify:
(
15
+
25
÷
5
)
×
12
4
10.
(15+25÷5)×12÷4+10.
2^11
2^11-2^5
1
2
3
=
