16p$^2$-25
prove that cot/1+tanθ=cotθ-1/2-sec²θ
25a$^2$-4
-11+x=-5+x
9n$^2$-1
16k$^2$-9
You sent
If P=(4,-1) is the midpoint of the segment AB, where A(2, 5), find B.
x= (a^3 +b^2- $\sqrt{\Box}$)/(a*b+c)
dy/dx=cot