(1/3)x-(1/4)x=1
Given two sequences x1(n) = {0,1, 2, 3, 4 }, y(n) = {1, 0, 0, 0, 0}; Determine a sequence x2(n) so that Y(k) = X1(k) X2(k)
(1/3)x+(1/4)x=1
1/3x-1/4x=1
2x-a= -1/2x then prove that 8x^3 + 1/8x^3 = a power 3 - 3a
3x^2
5 4/3+1/3=7
3x+7y+23=0
y=x squared-2
algebra
x-34=k
