5x+3=18
Convexity = $\frac{1}{P x(1+y)^2}$ $$\sum_{t=1}^{T}{C}$$($\frac{CF}{(1+Y)^t}$ (t^2 + t)
13×7+15×5+x=1000
4321+2636-2876+3785=
.3*.3*.3
x^2-6x-7=(x+a)^2+b find the value of a and b
a+c+5x=740000
a+c+7y=767000
b+c+5x=868000
a+3y=530000
square root of x^4 +64 - 16^2
a+c+5d=740000
a+c+7e=767000
b+c+5d=868000
a+3e=530000
Show that for all n > 1, 11| 3^(n+1) + 2^(4n+3).
