8+6i
find the square root
Differenciate y =cot 4x-3 from the first principle
$$\sum_{a}^{b}{C}$$
1 . 3/1-√3
2 . 3 /√3 + √12
3 . 7√3 /2√2+5
4 . √3 + √2 / √3 -2
ps these are fractions
half of the product of a number and 8, increased by the square of the number equals 50
12-7 10/22
half the product of a number and 8
x = 2300 + 0.75x
$x^{2}$ -6 .24x+0.0229
7 divided by 150
