roots of this soequation
r^3+150r^2-6400r+1000000=0
bˆ(2a)-4(a)ˆb=16
cubic solution for r^3+150r^2-6400r+1000000=0
two and three fifths times three and one third
bˆ(2a)-4(a)ˆb=256
x squared + 14x+48
1+cos2θ/sin2θ=cotθ
factorise
$9x^{2}$ +$3x^{3}$
9^x=25 what is 3^x=?
four and one third times six
