(3x - 4)(x - 5)
Point (-3,2)is on a circle with center at (4, 5). Find the circle's a.)radius b.)standard equation c.) general equation.
7x +15=3x+31
4/1×128/400×43/48
1+2
2×4×1×0×3×2
10⋅10\sqrt[]{10}\cdot \sqrt[]{10}10⋅10
300×400×500×600
644\sqrt[4]{\sqrt[]{64}}464
