Math Problem Solver

10(4x-1)=68+14x

(1+3–√3)3−3(1+3–√3)2+2(1+3–√3)−1

f(1+3–√3)

f(1+3–√3)=(1+3–√3)3−3(1+3–√3)2+2(1+3–√3)−1

20=9 80=x find x

f(1+3–√3)=(1+3–√3)3−3(1+3–√3)2+2(1+3–√3)−1

(1+3–√3)3−3(1+3–√3)2+2(1+3–√3)−1

2(x+3)=x-4

13(-2-11n)=-26+2n

∫

0

2π

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∫

π/4

π

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∫

0

2

​

ρ

4

1

​

ρ

2

sinϕdρdϕdθ.