3x-4/5<=5-x/-2
2d/9d/200=
partial fraction for (2z³+1)/(z(z+1))
d/dx(2xcos3x)
2x+3
cos2 theta-cos10 theta
xy dy/dx = y^2+1 / x^2+1
4n>3n+4
54 - (45.3 + 46.8) + 33.8
Solve for determinant Dk=∣[1,2k,2k−1],[n,n2+n+2,n2],[n,n2+n,n2+n+2]∣D_k=|[1,2k,2k-1],[n,n^2+n+2,n^2],[n,n^2+n,n^2+n+2]|Dk=∣[1,2k,2k−1],[n,n2+n+2,n2],[n,n2+n,n2+n+2]∣