write the time below using a 24 hour clock 4.00am 4.00pm
((7×20)−(9×1)+6−5+(9×2))−17
cosx=6x
1kg200g/2kg
5^-2+1
(9.5 -3x 1 1/2) /0.5
1kg200g/
2kg
Inverse function of
y=x^2*0.000008-0.0016x
(1.09*10^-3)*(5/3-x*8.8*10^3-0.5)^2=x
solve this
A bond with a face value of Rs. 1000 and a coupon rate of 12% is issued three years ago is redeemable after five years from now at...
