(x+1)(x+5)
(15cot36⁰)25³
(x+3)(x+5)
3x+4=25
f(x)=(3x + 5) (x^2 - 3)
2x - 7 =13
28 > 6x - 2
55,906,196,708,460,047,193,251,427,368,520 x 39 =
28 < 6x - 2
24 < 5x - 1