y(x+y) dx+(x+2y+1) dy=0nonexatc eqution
0.7054+2.58√((0.7054(1-0.7054))/104)
0.7054-2.58√(0.7054(1-0.7054)/104)
If a person draws five cards from a standard deck (without replacing them), what is the probability that at least one of the cards...
4x+1.5y=12.20
5x+2y=15.40
find x and y using simeltaneous equations
y=-3x^{2}+6x+9
5/3-1
(1)*($x^{2}$-1)*($x^{2}$+2x-15)
3 $\sqrt{20}$ +2 $\sqrt{\45}$ + $\sqrt{80}$