To find the square root of the complex number
z = 1 + root under 3
sum of -34 and 40 is subtracted from sum of -9 and -19
solve for x
2.51*10^6 = (0.000150+x)/((0.0863-x)(0.00313-x))
x = x + ∑x=0x=807x∗1023\sum_{x=0}^{x=807}{x*1023}x=0∑x=807x∗1023
x = x + ∑x807x∗1023\sum_{x}^{807}{x*1023}x∑807x∗1023
sum of -34and
40 is subtracted from sum of -9 and -19
manadar do ek parimey sankhya hai Siddh kijiye
Give proofs using contrapositive of the following statements.
1. For integers xy, if x+y is even, then x and y are both odd or b...
60/x + 180/(x-8)
60/x + 180/x-8
