6) Resolva o problema de valor inicial dado: $\mathbf{x}^{\prime}=\left[\begin{array}{rr}-\frac{5}{2} & \frac{3}{2} \\ -\frac{3}{2} & \frac{1}{2}\end{array}\right] \mathbf{x}, \quad \mathbf{x}(0)=\left[\begin{array}{l}3 \\ 1\end{array}\right]$...
4x:2=2+3*2
2x=A+B
6) $\mathbf{x}^{\prime}=\left[\begin{array}{rr}-\frac{5}{2} & \frac{3}{2} \\ -\frac{3}{2} & \frac{1}{2}\end{array}\right] \mathbf{x}, \quad \mathbf{x}(0)=\left[\begin{array}{l}3 \\ 1\end{array}\right]$...
A panel of 10 examiners was to interview two candidates and pick one of them for a job placement. 8 of them said candidate John wa...
x^2 - x - 6 =0
17+9-8-11+4=
240 + 0.75(y-150) + 200 + 200 = Y
150 + 0,85 (y-80) + 50 + 100 = y
3f+4=f+10