-5/2 4
(-3/2)3
34/53
20w3+10w3+7w3+4w3–41w3
find a solution to x^2 = 17 mod 128
-20/10
2 x ((6 minus 5 plus 3 squared ) plus 4 squared)
find a solution to x^2 is congruent to 17 mod 128
3x + 2y = -2 , 4x + 6y = -4 find x and y
2x$^{3}$−7x$^{3}$ +2x−7=0
