An open rectangular container is to have a volume (V ) of 62.5m3
. Determine the least surface area
(S) of material required.
Solve 𝑑𝑦
𝑑𝑥
=
𝑥−𝑦𝑐𝑜𝑠𝑥
𝑠𝑖𝑛𝑥+𝑦
, at 𝑦(1) = 2
5/10 +3/10
If x! = 6!7! then value of x
22X+11Y+10Z=95111
X=?
What is the value of
(
2
3
)
?
A
4
B
6
C
D
9
0= 1- 8/(t + 1)^3
(0.2 * 3) + (0.086 * 5) + (0.8) (0.914) (-2)
Find the valuve of 1.665 if 1=1.571