11 over 9 minus 17 over 12
87.6
fully simplify 8y+3-2y-7
4-2a+b=0
Prove algebraically that the sum of any six consecutive integers is divisible by 3
100÷30
x + 10 =15, what is x
73(5)
5−1+9
\sqrt[x]{x+y}=6,\:\left(x+y\right)\cdot 3^x=5832
