Math Problem Solver

1

4

b+1=

–

1

2

b+3

Solve for b.

1

4

b+1=

–

1

2

b+3

x^-0.23 = 0.454

0.9h=h–0.6

.1483448

27901442

.24970426

4720522

.5404430

88.44870

11294602

10398970

8+5f=

–

4f+1+8f

find equation of tangent of f(x)=x(x+2)(x-2)^2 at point x=a

9m+7=8m

1483448

27901442

24970426

4720522

5404430

0784488

11294602

10398970

9+5u=7u–9