(x*(x-3))/2=20
find the value of k if [3,1]is the solution of the given equation 5x-3ky=18
(-0,6.....) $^{-2}$
12a+4b-6c=10
4a+7b+2d=12
-6a+11c-4d=14
2b-4c+12d=8
-18 = -3 X -18 + 3
(-0,6 $\infty$ ) $^{-2}$
(3x - 2) are (x - 1) are factors of which of the following binomial expression
3x+5y=11 2x+3y=7
simplify $( \frac{ x^{2} }{4} )^{ -\frac{1}{2} }$
what number equals to 120 thousand when you take away 60% if it
