Converting measures (7 gal. + 16 qt. = gal.)
12-(8/3+3 divided by 2/3)
7 gal. + 16 qt. = gal.
3(X+8)=2(X+3)+10X
92436 / 9
y-1=1(x-(-1)) in standard form
3(X+8)=2(X+2)+10X
$\frac{x+3}{x^2+3x-4}$ = $\frac{x+2}{x^2-16}$
18/24
Substitute y= 4x +7 into the equation y+ 3x + 8, to find the value of x
