(60×3)−(50+25)+(30÷5)×(20−15)+100−(45÷9)+15
(100×3)−(50+25)+(40÷5)×(18−12)+25
(60×3)−(50+25)+(30÷5)×(20−15)+100−(45÷9)+10
A(2,-3) B(5,-6) and a point P on the line x-y=1 is such that PA-PB is maximum then find coordinates of B
(50×5)−5+(100/4)−(12−9)×2−30
find the nth term in the sequence:
14,11,8,5
(50×5)−5+(100/4)+(12−9)×3−30
solved (2√5 - 5)² + (3√2+√3)² - (√2-1)²
3g+2=7g-14
27. Divide 1000÷101000 \div 101000÷10.
