2x $^{2}$ + 8x + 2
-160=6x-8(5x+3)
Find the relative position of the line and the plane
c/6 -2=9
15-x=27-3x
$1/4^{5}$
1/3(5x−8)+2/3x
solve √35 - 6 √5
2x+12=50
6x+8=38-24
