\{0 \div (-4)\} + 4 =
y - 0.025y - 125 = 235.10, find the value of y?
(1-4x³)²
0 \div (-4) =
x ^ 2 - 25 = (x - 5)(x + 5) where x is real
7721 \div (-1) =
(18 - 3) + (9\times 2) - 6=
(-6) \times 6 \times (-6) =
(-6) \times (-6) \times (-6) =
