expand x+2 power-2/3 in powers of x
4x - 3 if x is 5
Simplify the following
2x−32^{x-3}2x−3 / 232^{3}23 =16
1 3/11
1 1/2
5/8(5/8)
∑abC\sum_{a}^{b}{C}a∑bC Solve it step by step. 4 power x minus 4 power minus x equals 16. 1 by 16.
4^xx-xxxxx-xx-xx-xxxxx-xx--xx-xx...
95x-114000
∏abC\prod_{a}^{b}{C}a∏bC *8*a^3*3
(-3) - (-12) =