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.989992293874963 .972828485072367 .20425403525235 .8408629 67156839.90265313553181635142 .00689 1380027.8719 .1697 .3162
Let $ABC$ be a triangle, such that the midpoint of $AB$ , the incenter and the touchpoint of the excircle opposite $A$ with \(\over...
.989992293874963 .972828485072367 .20425403525235 .8408629 67156839.90265313553181635142 .00689
.989992293874963 .972828485072367 .20425403525235 .8408629 .90265313553181635142 .00689
.989992293874963 .972828485072367 .20425403525235 8408629 .90265313553181635142 .00689
\frac{4m-5n}{p}=\frac{2m+7}{3} solve for m
.989992293874963 .972828485072367 .20425403525235 8408629.90265313553181635142 .00689
.989992293874963 .972828485072367 .20425403525235 8408629÷90265313553181635142 .00689
\frac{4m-5n}{p}=\frac{2m+7}{2} solve for m
.989992293874963 .972828485072367 .20425403525235 8408629 .00689

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