Math Problem Solver

5\frac{4}{5}+8\frac{1}{3}-\frac{23}{4}

49.1= A+B

A= $\frac{8}{100}$ (x)

B= $\frac{8}{100}$ (x-A)

\(x^{2}+x-\frac{30}{x}-5=1\)

\left(7^0+\sqrt{\frac{5^2-2^5}{-\left(2^3-3^{-2}\cdot 3^2\right)^{\:}}-1}\right)^5-\left(\frac{1}{4}\right)^{-2}

\left(7^0+\sqrt{\frac{5^2-2^5}{-\left(2^3-3^{-2}\cdot 3^2\right)^{\:}}-1}\right)^5-\left(\frac{1}{4}\right)^{-2}

\left(7^0+\sqrt{\frac{5^2-2^5}{-\left(2^3-3^{-2}\cdot 3^2\right)^{\:}}-1}\right)^5-\left(\frac{1}{4}\right)^{-2}