16*7
find the number of terms of an arithmetic series such that the sum is negative 8,common difference is 2 and the last term is 6.
graph f(x) =4x-6+1
X square plus one by X Square where X equals to 7-4 root three
6^2+9x
4/3 / (2/3 + 0.2/10)
24 x 6 =
write (5,-2) and (6,7) in y=mx+b
-1/2x*-3x
$\frac{\-2-3}{\-2}$