q2 plus 2q -8=0
16=2^x
4/9p^2+p-1
(5x +4) . (x+1) = 2x . (3x + 5) - X
y=xtanθ- (gx^2)/(2(√((gx_c)/2sinθcosθ))^2 〖cos〗^2 θ)
if a and a^-1 is invertible then eigen vectors are same?
x-y=4
x+y=14
4(x+3)-4(5x-2)
(x^2 - 18x + 81 = (x - a)^2)
lim sin 3xsquared/x as x approacher positive and negative infinity
