the weight of pet cats is normally distributed with a mean weight of 4.5kg and a standard deviation of 1 kg. calculate the probabi...
2x+11
(a+b)2 - (2a-2b)
(2.867/1000) + (8.92 x 10)
x + √x² + 3= 3x
x^2-16=0
x=?
g( x) =1/x
What's the differentiation ln(xy)=e^x+y
Y(t) =(t^4-2t^2+7t) / t^3
11.75% = (1+r)$^{1/2}$ -1
