−3+{−5−[−6+(−4−3)−(1−2)]−5}
(2- 1/3 x 3)
−10+{(−6+5)+[−3−(−8−2)+1]}=
(13−8)−{−4+[8−(9−3−7)+(−3−2)+5]−3+8}+9=
solve the monomials: 4x**2 y**2 * 3x*y
4x**2 y**2 * 3x*y
5+(2−(4+5−3)+6)−1−(3+5)=
5+[2−(4+5−3)+6]−1−(3+5)=
the sum of 4 consecutive integers is two. What is the least of these intergers
5+[2−(4+5−3)+6]−1−(3+5)
