∃𝑥 ∈ ℤ ∶ 2𝑥 + 1 = 4 ∨ 3𝑥 − 1 = −10
4a-3a when a=-2
4-(x+3)>3(3-x)
h-2k+5=0
2h+3k-1=0
-2(x+2)3(y-8)
5×3-2+1×2=
168 divide by 12
3x-y=-1
3 1/9 / 1 1/6
if a|c and b|c then a . c|b