3root3 times 3 =
raiz cubica de 8
[(3-1i)+(-2-4i)]* i3i^{3}i3 +[(1-2i)*(1-2i)]
6=5x+2-4x
1 plus 8 divided by 2 cross times 2 equals
i3i^{3}i3
x^2-3x-4=0
[(0+2i)+(-3-1i)]*[1+2i-(2+4i)]
x^2 - y^2 = 60
Find rational numbers 𝑎 and 𝑏, such that 4+3√5 / 4-3√5 =𝑎+𝑏√5
