0.8451 to 2 d.p
find the value of 2^-3 x 3^-2
solve x −√(25 − x^2) = 1
solve x −√(25 − x^2)^2 = 1
233 mod 105
(7*12)-3 at the potence of 12
0.3741 to 2 decimal places
solve x −(√25 − x^2)^2 = 1
(-3a^2+6a-1)-(-2a^2+3a-1)
Find the values of a, b and c such that the system of equations has
i. exactly one solution ii. infinite solutions iii. no soluti...
