10 $\sqrt{1/10}$
2x^3-21x^2+40x+63 divided by x+1
Using Modified Eluers method, find an approximate value of y when
x = 0.3, given that
dy
- =x+y and y=1 when x = 0
dx
avarege of 2 numbers is 6. one number is 7,what is the seceond number
limite de x tendiendo a cero de ln (1+x)-senx dividido x por senx
(1+12%)^3
(x^2+y^2)dx-(xy+x^2)dy=0
. Solve the system of equations by Cramer’s Rule
5x - 7y + z = 11, 6x − 8y - z = 15, 3x + 2 y - 6z = −5
((2.76-4.11)^2+(3.72-4.11)^2+(1.5-4.11)^2+(3.37-4.11)^2+(9.25-4.11)^2+(4.08-4.11)^2)/(6-1)
