Solve 2 ^ (2x + 3) - 9 * 2 ^ x + 1 = 0

asked by guest
on Jan 31, 2025 at 12:37 am



You asked:

Solve the equation 22x+392x+1=0{2}^{2 x + 3} - 9 \cdot {2}^{x} + 1 = 0 for the variable xx.

MathBot Answer:

The 2 solutions to the equation are: x=0x=log(8)log(2)3.0\begin{aligned}x &= 0\\x &= - \frac{\log{\left(8 \right)}}{\log{\left(2 \right)}} \approx -3.0\end{aligned}