radical of 2x +3=9 find x
You asked:
Solve the equation \[\sqrt{2} \cdot x + 3 = 9\] for the unknown \(x\).
MathBot Answer:
The solution is: \[x = 3 \sqrt{2} \approx 4.2426407\]
\[\begin{aligned}\sqrt{2} x + 3 &= 9\\\sqrt{2} x &= 6\\x &= 3 \sqrt{2}\end{aligned}\]