-8y+6x=36
6x-y=15
solve it by elimination
You asked:
Solve the system of equations \(-\left( 8 y \right) + 6 x = 36\), \(6 x - y = 15\) by elimination.
MathBot Answer:
\[\begin{aligned}x &= 2\\y &= -3\end{aligned}\]
\[\begin{aligned}6 x - 8 y &= 36\\6 x - y &= 15\end{aligned}\]
Eliminate \(x\) from equation 2 by multiply both sides of equation 1 by \(-1\), and adding the results to both sides of equation 2.
\[\begin{aligned}6 x - 8 y &= 36\\7 y &= -21\end{aligned}\]
Solve equation 2 for \(y\), and substitute the solution into the remaining equations.
\[\begin{aligned}6 x &= 12\\y &= -3\end{aligned}\]
Solve equation 1 for the remaining unknown \(x\).
\[\begin{aligned}x &= 2\\y &= -3\end{aligned}\]