log 6x + 10x + 12

asked by guest
on Nov 23, 2024 at 4:34 am



You asked:

Evaluate the expression: \(\log\left( 6 x \right) + 10 x + 12\)

MathBot Answer:

Evaluated



\(\displaystyle \log\left( 6 x \right) + 10 x + 12 = 10 x + \log{\left(6 x \right)} + 12 \)

Factored

\[\log\left( 6 x \right) + 10 x + 12 = 10 x + \log{\left(x \right)} + \log{\left(6 \right)} + 12\]

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