6K^2-4K^3-1=0

asked by guest
on Nov 29, 2024 at 3:41 am



You asked:

Solve the equation \(6 {K}^{2} - 4 {K}^{3} - 1 = 0\) for the variable \(K\).

MathBot Answer:

The 3 solutions to the equation are: \[\begin{aligned}K &= \frac{1}{2} = 0.5\\K &= \frac{1}{2} - \frac{\sqrt{3}}{2} \approx -0.3660254\\K &= \frac{1}{2} + \frac{\sqrt{3}}{2} \approx 1.3660254\end{aligned}\]