s^3 + 7s^2 + 49s = 0

asked by guest
on Nov 23, 2024 at 8:05 am



You asked:

Solve the equation \({s}^{3} + 7 {s}^{2} + 49 s = 0\) for the variable \(s\).

MathBot Answer:

The 3 solutions to the equation are: \[\begin{aligned}s &= 0\\s &= - \frac{7}{2} - \frac{7 \sqrt{3} i}{2} \approx -3.5 -6.0621778 i\\s &= - \frac{7}{2} + \frac{7 \sqrt{3} i}{2} \approx -3.5 + 6.0621778 i\end{aligned}\]


\(i\) is the imaginary unit, defined as \(i^2 = -1\).