3(3x+4/2)-2(-x-1)-(-x+6/2)-9=0
You asked:
Solve the equation \(3 \cdot \left(3 x + \frac{4}{2}\right) - 2 \cdot \left(-x - 1\right) - \left(-x + \frac{6}{2}\right) - 9 = 0\) for the variable \(x\).
MathBot Answer:
The solution is: \[x = \frac{1}{3} = 0.\overline{3}\]
\[\begin{aligned}3 \cdot \left(3 x + \frac{4}{2}\right) - 2 \cdot \left(-x - 1\right) - \left(-x + \frac{6}{2}\right) - 9 &= 0\\12 x - 4 &= 0\\12 x &= 4\\x &= \frac{1}{3}\end{aligned}\]