(6+i)(-i)

asked by guest
on Nov 23, 2024 at 4:41 am



You asked:

Evaluate the expression: \(\left(6 + i\right) \cdot -i\)

MathBot Answer:

Evaluated



\(\displaystyle \left(6 + i\right) \cdot -i = - i \left(6 + i\right) \)

Expanded

\[\left(6 + i\right) \cdot -i = 1 - 6 i\]

\(i\) is the imaginary unit, defined as \(i^2 = -1\).

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