Problem 1:
𝑔
(
𝑥
)
=
8
−
4
𝑥
3
+
2
𝑥
8
g(x)=8−4x
3
+2x
8
Derivative:
𝑔
′
(
𝑥
)
=
−
12
𝑥
2
+
16
𝑥
7
g
′
(x)=−12x
2
+16x
7
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
Problem 1:
𝑔
(
𝑥
)
=
8
−
4
𝑥
3
+
2
𝑥
8
g(x)=8−4x
3
+2x
8
Derivative:
𝑔
′
(
𝑥
)
=
−
12
𝑥
2
+
16
𝑥
7
g
′
(x)=−12x
2
+16x
7
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.