0=e^{-2y}

asked by guest
on Nov 23, 2024 at 7:45 am



You asked:

Investigate the equation: \(0 = {e}^{-\left( 2 y \right)}\).

MathBot Answer:

No solution.

\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).

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