24*n^2 + 52*n + 29

factorize

asked by guest
on Nov 23, 2024 at 7:15 am



You asked:

Factor the expression: \(\displaystyle 24 {n}^{2} + 52 n + 29\)

MathBot Answer:

Factorization over the real numbers:

\[52 \cdot \left(0.461538461538462 n^{2} + 1 n + 0.557692307692308\right)\]

Factorization over the complex numbers:

\[24 \left(n + \left(\frac{13}{12} - \frac{\sqrt{5} i}{12}\right)\right) \left(n + \left(\frac{13}{12} + \frac{\sqrt{5} i}{12}\right)\right)\]


\(i\) is the imaginary unit, defined as \(i^2 = -1\).